A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential, capacitance respectively are.
Text Solution
Verified by ExpertsThe correct answer is:
D
As the capacitor is isolated after charging. Charge on it remains constant. Plate separation d increases, capacitance decreases as 
and hence, potential increases at 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two equal negative charge – q are fixed at the fixed points and on the Y-axis. A positive charge …
An electric line of force in the xy plane is given by equation . A particle with unit positive cha…
A positively charged ball hangs from a silk thread. We put a positive test charge at a point and m…
If on the concentric hollow spheres of radii r and the charge is distributed such that their surf…
Two equal charges of opposite sign separated by a distance constitute an electric dipole of dipol…
A point charge q is placed at a distance a/2 directly above the center of a square of side a. The e…